Ab reacts with c2 to yield ac and b. 2ab+c2--> 2ac+2b the molar mass of ab is 75.0 g/mol, the molar mass of ac is 60.0 g/mol, and the molar mass of b is 50.0 g/mol. a) what is the theoretical yield (in grams) of ac from the reaction of 41.0 g of ab? b)if the reaction produced 16.5 g of ac, what was the percent yield?

Question  A

the theoretical  yield  of Ac  is  calculated as  follows

calculate  the  moles  of  AB = mass/molar mass
=41 g/75  g/mol  = 0.55  moles

2AB +C2 = 2AC + 2B

by  use  of  mole  ratio  between  AB :  AC  which  is  2:2 or  1:1 the moles   of AC  is also 0.55  moles

theoretical  mass is  therefore =  moles  x molar  mass 
= 0.55   x  60 = 33  grams

          question B
THe  % yield =  actual  yield/theoretical  yield  x  100

=  16.5g/33 g  x100 =50% of  AC