Given that a 741 op-amp will be used for U1, L1 = 28.1 mH, RL = 33.5 Ω for the nominal 33 mH inductor, and C1 = 0.1 µF, find values of R1 such that α = 5 ω0, α = ω0, and α = 0.2 ω0. Show all of your work. Limit your solutions to 3 significant figures.

1. may 2. september 3. february, and december4. 70°f

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j