There are no attached choices of Punnet square, but the answer could be concluded, knowing the genotypes of parents.
Inheritance is a bit complicated in a sex-linked trait because there are two X chromosomes in females and one X chromosome and one Y chromosomes in males.
In females, the situation is similar as in autosomal traits because they have two X chromosomes. The presence of only one dominant allele is enough for a dominant trait to express in females. But in males is different. Red eye color is dominant, thus, male with dominant allele on X chromosome will have red eyes. The same is with white eye color in males.
Therefore, to have all of the offspring with red eyes, mother must have red eyes and genotype (XrXr - two dominant alleles). The genotype of the father will not affect the offspring in this case:
If
Xr - dominant allele on X chromosome for red eyes,
Xw - recessive allele on X chromosome for red eyes,
Y - Y chromosome,
Then:
XrXr - female with red eyes,
XrXw - female with red eyes,
XwXx - female with white eyes,
XrY - male with red eyes,
XwY - male with white eyes.
Now, let's cross different combinations.
mother father
P: XrXr XrY
F1: XrXr XrXr XrY XrY
All of the offspring, including both female (XrXr) and male (XrY) will have red eyes.
Similarly:
mother father
P: XrXr XwY
F1: XrXw XrXw XrY XrY
But, if the mother is heterozygous (XrXw) with red eyes or recessive homozygous (XwXw), not all of the offspring will have red eyes, even if the father has red eyes. For example:
mother father
P: XrXw XrY
F1: XrXr XrXw XrY XwY
Thus, all of the female offspring will have red eyes (XrXr or XrXw), but half of the male offspring will have white eyes (XwY).