Avase with a mass of 0.800 kilograms falls from a height of 0.750 meters to a position of 0.500 meters above the floor. ignoring frictional effects, the kinetic energy at the 0.500 position is

The kinetic energy at the 0.500 position is 1.96 J.

Explanation:

Mass of the vase = 0.800 kg

Height from where vase fallen = 0.750 m

Potential energy of vase at 0.750 m:

Kinetic energy of the vase at the point just before it was about to fell:

(absence of motion)

P.E + K.E = 5.88 J + 0 J = 5.88 Joules

Potential energy of vase at 0.500 m:P.E'

Kinetic energy of the vase at the point 0.500 m above the floor: K.E'

As we know, that sum of P.E and K.E remains constant.;

P.E' + K.E' = 3.92 J + K.E' = 5.88 J

K.E' = 5.88 J - 3.92 J = 1.96 J

The kinetic energy at the 0.500 position is 1.96 J.

12 is it do you think so