How many grams of carbon monoxide are needed to react with an excess of iron (iii) oxide to produce 198.5 grams of iron? fe2o3(s) + 3co(g) --> 3co2(g) + 2fe(s) show work so i can understand the concept

The grams  of   carbon monoxide  is 148. 68 g

calculation

Fe₂O₃(s)  + 3CO (g) →   3 CO₂(g)  + 2Fe (s)

 Step 1: find  the moles  of  CO

   moles = mass÷ molar mass

 from periodic table the  molar mass of Fe =56 g/mol

 moles =  198.5 g÷ 56 g/mol =3.54  moles

Step 2 : use the mole ratio to determine the  moles of  Co

 from given equation  Co: Fe is 3: 2

therefore the  moles of CO = 3.54 moles  x 3/2= 5.31 moles

Step 3 Find mass of Co

mass  =  moles × molar mass

from periodic table the  molar mass of CO = 12+ 16 = 28 g/mol

= 5.31  moles × 28 g/mol = 148.68  g

the answers would be

the first one and the second one

it takes on an electronical energy