2300 g = 2.3 kg.
∵ The density of the solution = mass of the solution/volume of the solution.
The density of the solution = 1.15 g/mL, volume of the solution = 2.0 L = 2000.0 mL.
∴ The mass of the solution = (density of the solution)(volume if the solution) = (1.15 g/mL)(2000.0 mL) = 2300 g = 2.3 kg.
The mass of intravenous glucose solution is 2300 g
To calculate the mass of solution, we use the equation:
Volume of glucose solution = 2.00 L = 2000 mL (Conversion factor: 1 L = 1000 mL)
Density of glucose solution = 1.15 g/mL
Putting values in above equation, we get:
Hence, the mass of intravenous glucose solution is 2300 g
1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄
2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%