Chemistry, 10.07.2019 02:10 Animallover100
The dissociation of molecular iodine into iodine atoms is represented as i2(g) ⇌ 2i(g) at 1000 k, the equilibrium constant kc for the reaction is 3.80 × 10–5. suppose you start with 0.0456 mol of i2 in a 2.30-l flask at 1000 k. what are the concentrations of the gases at equilibrium?
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The dissociation of molecular iodine into iodine atoms is represented as i2(g) ⇌ 2i(g) at 1000 k, th...
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