Ablock of copper of unknown mass has an initial temperature of 65.4 ∘c. the copper is immersed in a beaker containing 95.7 g of water at 22.7 ∘c. when the two substances reach thermal equilibrium, the final temperature is 24.2 ∘c. what is the mass of the copper block? express your answer in grams to three significant figures.

The mass of the copper block in grams is calculated to be 37.9g

HOW TO CALCULATE MASS IN COLORIMETRY.

The mass of a substance in colorimetry can be calculated by using the formula below:

Q = m × c × ∆T

Where;

Q = amount of heat absorbed or released (J)m = mass of substance (g)c = specific capacity of substance (J/g°C)∆T = change in temperature (°C)

In this case;

Q(water) = -Q(copper)

m.c.∆T (water) = -m.c∆T (copper)

As given in this question;

FOR WATER:

m = 95.7gc = 4.184 J/g°C∆T = 24.2°C - 22.7°C = 1.5°C

FOR COPPER:

m = ?c = 0.385 J/g°C∆T = 24.2°C - 65.4°C = -41.2°C

m.c.∆T (water) = -m.c∆T (copper)

95.7 × 4.184 × 1.5 = - (m × 0.385 × -41.2)

600.6132 = -(-15.862m)

600.6132 = 15.862m

m = 600.6132 ÷ 15.862

m = 37.9g

Therefore, the mass of the copper block in grams is calculated to be 37.9g.

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The mass of the copper block: 37,829 g

Further explanation

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released

Q in = Q out

Heat can be calculated using the formula:

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

1. H₂O

m = 95.7 g

c = 4.18 J / gºC

delta T = 24.2 °C - 22.7 °C = 1.5 °C

Q H₂O = 95.7 x 4.18 x 1.5

Q H₂O = 600,039 J

2. Cu

c = 0.385 J / gºC

delta T = 65.4 °C - 24.2 °C = 41.2 °C

QH₂O = Q Cu

600,039 J = m. 0.385 J / gºC. 41.2. °C

Learn more

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Specific heat

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When heat is added to a substance

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