At equilibrium, the concentrations in this system were found to be [n2]=[o2]=0.200 m and [no]=0.600 m. n2(g)+o2(g)↽−−⇀2no(g) if more no is added, bringing its concentration to 0.900 m, what will the final concentration of no be after equilibrium is re‑established?

0.84M

Explanation:

Hello,

At first, the equilibrium constant should be computed because the whole situation is at the same temperature so it is suitable for the new condition, thus:

Now, the new equilibrium condition, taking into account the change x, becomes:

Nevertheless, since the addition of NO implies that the equilibrium is leftward shifted, we should change the equilibrium constant the other way around:

Thus, we arrange the equation as:

Finally, the new concentration is:

Best regards.

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