Name and draw the structure of the simplest hydrocarbon that contains at least one primary, one secondary, and one tertiary position in the same molecule. give the total number of possible monochlorinated products (all possible constitutional isomers and stereoisomers) that could be obtained from the free radical chlorination of this compound give the structure of all the monochlorinated products

The compound will be: 2,2-dimethylbutane

The total number of possible isomer of mono chlorinated product will be: four

Explanation:

Primary carbon is one which has three hydrogens

Secondary carbon is one which is directly attached to two carbons

Tertiary carbon is one which is directly attached to three carbons

The compound will be: 2,2-dimethylbutane

The total number of possible isomer of mono chlorinated product will be: four

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.