Chemistry, 24.02.2020 21:03 Kyliehayden05
Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where its temperature is 105°C. What is the fraction of the steam in its initial state?
Answers: 1
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Using a value of ksp = 1.8 x 10-2 for the reaction pbcl2 pb+2(aq) + 2cl -(aq). if the value of ksp was determined to be only 1.2 x 10-2: too much solid has dissolved. additional precipitate is forming. the solution is unsaturated. the ions are now combining to reduce their concentrations.
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Imagine that you push on a large rock. at what point does your effort change the rock’s mechanical energy?
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Wet steam at 1100 kPa expands at constant enthalpy (as in a throttling process) to 101.33 kPa, where...
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