Use the reactions below and their equilibrium constants to predict the equilibrium constant for the reaction 2A(s)⇌3D(g)2A(s)⇌3D(g). A(s)A(s) ⇌⇌ 1212 B(g)+C(g), K1=0.0334B(g)+C(g), K1=0.0334 3D(g)3D(g) ⇌⇌ B(g)+2C(g), K2=2.35

K = 0,0285

Explanation:

It is possible to obtain the equilibrium constant of a reaction using the sum of another different reactions. In this case the reactions are:

(1) A(s) ⇌ 1/2 B(g) + C(g), K1=0.0334

(2) 3D(g) ⇌ B(g) + 2C(g), K2=2.35

2*(1) 2A(s) ⇌ B(g) + 2C(g), 2* K1 = 2* 0.0334 = 0,0668

-(2) B(g) + 2C(g) ⇌ 3D(g)  1/K2 = 1/2,35 = 0,426

2*(1) - (2): 2A(s) ⇌ 3D(g) K = 0,0285

I hope it helps!

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