If I have 340 mL of a 0.5 M NaBr solution, what will the concentration be if I add
400 mL more water to it?
A. 0.03 molar
B. 0.13 molar
C. 0.23 molar
D. 0.33 molar

Option C. 0.23 molar

Explanation:

The following data were obtained from the question given:

C1 = 0.5 M

V1 = 340mL

V2 = since 400mL was added to the original volume, therefore = 340 + 400 = 740mL

C2 =?

The concentration of the diluted solution can be calculated by using the following:

C1V1 = C2V2

0.5 x 340 = C2 x 740

Divide both side by 740

C2 = (0.5 x 340) / 740

C2 = 0.23M

Therefore, the new concentration of the solution is 0.23M

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.