What is the molarity of a solution that has 2.0 mol of MgF2 dissolved in enough water to make 1.29 L of solution?

[MgF₂] = 1.55 M

Explanation:

Molarity → mol/L

A sort of concentration where are indicated the moles of solute contained in 1L of solution

Moles of solute: 2 moles

Volume of solution 1.29L

M = 2 mol / 1.29L = 1.55M

The molarity of MgF2 is 1.55 M

Explanation:

Step 1: Data given

Number of moles MgF2 = 2.0 moles

Volume of solution = 1.29 L

Molar mass MgF2 = 62.3 g/mol

Step 2: Calculate molarity of the MgF2 solution

Molarity MgF2 = moles MgF2 / volume solution

Molarity MgF2 = 2.0 moles MgF2 / 1.29 L

Molarity MgF2 = 1.55 mol/L = 1.55 M

The molarity of MgF2 is 1.55 M

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j