What is the solubility of calcium sulfate (CaSO4) in 0.30 M aqueous sodium sulfate (Na2SO4)? (Ksp of calcium sulfate = 2.0 x 10^-5

Therefore the solubility of CaSO₄ in Na₂SO₄ is  =907.12 g/L.                                                                          

Explanation:

           CaSO₄   →    Ca²⁺  +   SO₄²⁻

Initially   0                  0              0

Finally    s                   s                s

........(1)

Na₂SO₄        →        Na²⁺  +   SO₄²⁻

Given, the concentration of Na₂SO₄ is 0.30 M .

Then [Na²⁺] = [SO₄²⁻] = 0.30  

Putting the value of and  [SO₄²⁻] in equation (1)

                = 6.67×10⁻⁵

The atomic mass of CaSO₄  is 136 g/mol

Therefore the solubility of CaSO₄ in Na₂SO₄ is = (6.67×10⁻⁵×136)g/L

                                                                               =907.12 g/L

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l