A chemist must dilute 62.8mL of 167.μM aqueous zinc oxalate ZnC2O4 solution until the concentration falls to 57.0μM . He'll do this by adding distilled water to the solution until it reaches a certain final volume.

184 mL.

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 62.8 mL

Initial concentration (C1) = 167 μM

Final concentration (C2) = 57.0 μM

Final volume (V2) =?

To obtain the final volume of the solution, we shall apply the dilution formula as follow:

C1V1 = C2V2

167 × 62.8 = 57 × V2

10487.6 = 57 × V2

Divide both side by 57

V2 = 10487.6 / 57

V2 = 183.99 ≈ 184 mL

Therefore, chemist must add distilled water to the solution until it reaches a volume of 184 mL.

b

explanation:

mitosis

the term hydride is commonly named after binary compounds that hydrogen forms with other elements of the periodic table. hydride compounds in general form with almost any element, except a few noble gases. the trends and properties vary according to the type of intermolecular force that bonds the elements together, the temperature, its molecular masses, and other components. hydrides are classified into three major groups, depending on what elements the hydrogen bonds to. the three major groups are covalent, ionic, and metallic hydrides. formally, hydride is known as the negative ion of a hydrogen, h-, also called a hydride ion. because of this negative charge, hydrides have reducing, or basic properties. its special characteristics will be further discussed.

explanation: