Write the thermochemical equation for the combustion of acetylene, C2H2 (g), in oxygen, for which the standard enthalpy of reaction is -1300 kJ per mole of acetylene.

C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l)   ΔH° = -1300 kJ/mol

Explanation:

In the combustion of acetylene, it reacts with oxygen to produce carbon dioxide and water. The corresponding chemical equation is:

C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l)

The thermochemical equation includes the balanced chemical equation, stating the states of aggregation and the enthalpy of the reaction.

C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l)   ΔH° = -1300 kJ/mol

the answer is:  

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