10.0 grams of a gas occupies 12.5 liters at a pressure of 42.0 mm Hg. What is the volume when the pressure has increased to 75.0 mm Hg? 6.72 L 7.00 L 22.3 L 0.143 L

 7.00 L

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

    (At constant temperature and number of moles)

where,

= initial pressure of gas  = 42.0 mm Hg

= final pressure of gas  = 75.0 mm Hg

= initial volume of gas   = 12.5 L

= final volume of gas  = ?

Therefore, the volume  when the pressure has increased to 75.0 mm Hg is 7.00 L

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