How many mL of solution are required to make a 0.270M solution of sodium chloride if you have 2.18g of sodium chloride?

138mL are required to make the solution

Explanation:

A solution of 0.270M contains 0.270 moles of solute (NaCl in this case), per liter of solution.

To solve this problem we need to determine the moles of NaCl in 2.18g. With these moles and molarity we can find the volume required to prepare the solution:

Moles NaCl -Molar mass: 58.44g/mol-:

2.18g * (1mol / 58.44g) = 0.0373moles NaCl

Volume of solution:

0.0373moles NaCl * (1L / 0.270moles) = 0.138L

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