Determine the oxidation number of sulfur in S203 ( with steps)

The oxidation number of sulphur in is +2

Explanation:

S2O3 2-

2 (S) + 3(O)=-2

2 (S) + 3(-2)=-2

2 (S) + (-6) =-2

2 S = +4

S= +2

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.