How many total electrons are transferred in the redox reaction? Al (s) + Cr(NO3)2 (aq) – Cr (s) + Al(NO3)3 (aq)

A. 2
B. 3
C. 5
D. 6

Option D.

Explanation:

Let's balance the hole reaction by the ion electron method.

Al (s) + Cr(NO₃)₂ (aq) – Cr (s) + Al(NO₃)₃ (aq)

We know that oxidation state at ground state is 0.

We determine the half reactions:

Al  ⇆   Al³⁺  +  3e⁻

Aluminum increase the oxidation state. This is the oxidation.

Cr²⁺ + 2e⁻  ⇄   Cr

Chromium decrease the oxidation state. It changed from +2 to 0.

This is the reduction. In order to balance the half reactions, we need to multiply by 2 and by 3. In that way, we can cancel the electrons:

(Al  ⇆   Al³⁺  +  3e⁻) . 2

(Cr²⁺ + 2e⁻  ⇄   Cr) . 3

We sum the half reactions:

2 Al + 3 Cr²⁺  +  6e⁻  ⇄  2Al³⁺  +  6e⁻ + 3Cr

We cancel the electrons, so now the balanced reaction is:

2Al + 3Cr(NO₃)₂  →  3Cr  + 2Al(NO₃)₃

Final 6 electrons are transferred in the redox reaction.

c. is the answer

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water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.