Calculate the molarity of 0.300 mol of na2s in 1.75 l of solution.

calculate the molarity of 31.3 g of mgs in 955 ml of solution

First equation:
molarity=
no.of moles of solute (Na2S)/volume of solution
0.300/1.75 = 0.171
second equation:
same law
but in volume it is milliliter so you have to convert it by multiplying it with 10^-3
(10 power -3)

to understand it clearly
see this
http://imgur.com/xTS35QM

Ithinks its false. tell me if im wrong