Given 2.91 moles of a gas in a 500 milliliter-container, if the temperature is found to be 31 degrees celsius, what is the pressure of the gas? (the ideal gas constant is 0.0821 l · atm/mol · k.)
1.45 x 102 atm
1.48 x 101 atm
1.45 x 10-1 atm
1.45 x 101 atm

The pressure of the gas comes out to be

Explanation:

To calculate the pressure of the gas, we use the equation given by ideal gas equation, which is:

where,

P = Pressure of the gas = ? atm

V = Volume of the gas = 500 mL = 0.5 L    (Conversion factor: 1 L = 1000 mL)

n = Number of moles of gas = 2.91 moles

R = Gas constant =

T = Temperature of the gas =

Putting values in above equation, we get:

Hence, the pressure of the gas comes out to be

5.6⋅10−^19  j

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