How many moles of agno3 must react to form 0.854 mol ag?

The
The equation of its dissolution in water is: AgNO3 → Ag + (aq)  +  NO3- (aq)

and     AgNO3 →   Ag + (aq)  +  NO3- (aq)
          1 mol          1mol                1mol 
             ?     0.854mo
so for finding the value, it is sufficients to complute 1 x 0.854 mol =0.854 mol
so,  0.854 mol is required for the reaction to form 0.854 mol of Ag

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