Acompound with a molar mass of 100.0 g/lol has an elemental composition of 24.0% c, 3.0% h, 16.0% o and 57.0%f. what is the molecular formula of the compound?

If I made no mistake in calculation, the given answer must be correct...(tried my best)

elements   :                        carbon     hydrogen    oxygen       Fluorine

 composition [C]                     24             3                16                57

M r                                          12             1                16                19

(divide C by Mr)                       2               3                 1                  3

(Divide by smallest value)       2                3                  1                  3

(smallest value = 1...so all value remained constant)

Empirical formula : C2H3OF3

if molar mas = 100 g per mole, then

first step calculate Mr. of empirical formula:  [= 100]

Them molecular formula = empirical formula