Copper has a density of 8.96 g/cm3 . if a cylinder of copper weighing 48.85 g is dropped into a graduated cylinder containing 20.00 ml of water, what will be the new water level?

To solve for the new water level, let us first calculate for the volume of the copper cylinder. The formula we can use is:

V = m / ρ

where V is the volume, m is the mass of the copper and ρ is the density, therefore:

V = 48.85 g / (8.96 g / cm^3)

V = 5.45 cm^3

since cm^3 = mL

V = 5.45 mL

The new water level will be the initial volume of the graduated cylinder plus the volume of the copper cylinder, therefore:

new water level = 20 mL + 5.45 mL

new water level = 25.45 mL

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the answer is minerals.