Arrange the following aqueous solutions in order from smallest to greatest freezing point depression: 0.400 m CaCl2, 0.400 m glucose or 0.400 m NaCl, Then determine the freezing point depression for each. For water, Kf = 1.86°C/m.

glucose<NaCl<CaCl2

Explanation:

Hello there!

In this case, since the general equation for the calculation of the freezing point depression is:

Whereas m and Kf are the same for the given salts, then we conclude that the greatest freezing point is exhibited by the salt with the greatest Van't Hoff's factor and the smallest freezing point with the smallest Van't Hoff's factor. In such a way, since this factor is equal to the number of ionized species, we infer that CaCl2 has i=3, glucose i=1 (nonionizing) and NaCl i=2; therefore, the order from smallest to greatest is:

glucose<NaCl<CaCl2

Regards!

you need to give more information

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6