You are mixing x ml of wine, which is 0.0030 m in sugar, with 20.0 ml of wine, which is 0.00010 m in sugar. the resulting wine is mixed with 30.0 ml of wine, which is 0.0020 m in sugar. the resulting wine is 0.0015 m in sugar. what is the value of x? assume that the volumes are additive.

The rule that we will use to solve this problem is:
M1V1 + M2V2 + M3V3 = MtVt
where:
M1 is the molarity of first solution = 0.003 molar
V1 is the volume of the first solution which is the X that we want to find
M2 is the molarity of second solution = 0.0001 molar
V2 is the volume of second solution = 20 ml
M3 is the molarity of third solution = 0.002 molar
V3 is the volume of the third solution = 30 ml
Mt is the final total molarity = 0.0015 molar
Vt is the final volume = V1+V2+V3 = X+20+30 = (X+50) ml

Substitute with the above givens in the equation to get X as follows:
0.003X + 0.0001(20) + 0.002(30) = (X+50)(0.0015)
0.003X + 0.062 = 0.0015X + 0.075
0.003X - 0.0015X = 0.075 - 0.062
0.0015X = 0.013
X = 0.013 / 0.0015 
X = 8.667 ml

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer