Asteel block has a volume of 0.08 m³ and a density of 7,840 kg/m³. what is the force of gravity acting on the block (the weight) in water? a. 6,150.64 n b. 5,362.56 n c. 7,600.18 n d. 6,700.56 n

Correct Option a. 6150.64 N

Weight (w) is defined as:

w = mg

So, first we need to find the mass (m) of the steel block using its volume and density.

Mass = Density x Volume 
So,
m = 0.08 x 7840 = 627.2 g

Using value of m and g = 9.807, we get

w = 627.2 x 9.807 = 6150.95 Newtons

Therefore, option a is the correct answer. 
The slight difference is because the value of g is rounded of to 3 decimal cases.