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What will happen if scanf encounters the string "vivaciuosly"when scanning a value for str?
a. since there is not enough room in str forthe whole string, only "vivaciously" will be stored in str
b. function scanf will store the entirestring "vivaciously", even though there is insufficient space instr
c. the program will abort with an errormessage
d. only "vivacious" will be scanned andstored, leaving "ly" on the input line
e. none of the above

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What will happen if scanf encounters the string "vivaciuosly"when scanning a value for str?
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