Days of the week are represented as three-letter strings ("mon", "tue", "wed", "thu", "fri", "sat", "sun"). write a javascript function solution that, given a string s representing the day of the week and an integer k (between 0 and 500), returns the day of the week that is k days later. for example, given s = "wed" and k = 2, the function should return "fri". given s = "sat" and k = 23, the function should return "mon".

function getDay(s, k){

var weekDays = ["Mon","Tue","Wed","Thu","Fri","Sat","Sun"];

var index=weekDays.findIndex(function(weekDay){return weekDay==s;});

return weekDays[(index+k)%7];

}

Explanation:

//this functions receive the next parameters:

//s which is the day of the week

//k the number of days after s week day

function getDay(s, k){

var weekDays = ["Mon","Tue","Wed","Thu","Fri","Sat","Sun"];

//variable index is the index in list weekDays of s

var index=weekDays.findIndex(function(weekDay){return weekDay==s;});

//use module operator % to get the remainder of the division (index+k)/7

//return the string value of the day

return weekDays[(index+k)%7];

}