Your local high school has challenged you to them challenge their students by building such a stone supercomputer with them. no, they don't have all 128 of those old pc/xts sitting around just maybe only a dozen to start with. but if they can make it work with this year's students, they'd love to keep growing it. what sort of network design do you want to recommend that they look at -- knowing that none of them can afford to buy a 128-port switch or router right up front? how could your network grow to accommodate this project? does allowing / encouraging the use of wireless as well as wired switches and routers you do this, or only make things more complicated and run slower?

Explain why it is reasonable to assume that receiving 3 duplicate acks in tcp is an indication that the network is not currently congested.

You will be given two character arrays of the same size, one will contain a number of ships. ships will move around the character array based on which way they are facing and the route they are on. routes are given in the other array. the route consists of '-' and '|' for straight paths, '\' and '/' for curves, and '+' for intersections. there are ships on these routes. ships always face a direction, '^' for up, '> ' for right, 'v' for down, and '< ' for left. any time the ships hit a '\' or a '/' it will turn as you would expect a ship to turn (e.g. a '^' that moves into a '/' will turn right). at an intersection, ships will always continue straight through. all ships move at the same speed, ships take turns moving and all ships move during one 'tick'. the one in the most top left goes first, followed by those to its right, then the ones in the next row. it iterates along the rows and then down the columns. each ship moves one space on its turn moving along the route. your function needs to return the position of the first collision between two ships and the number of ticks before the crash occurred.

1. for which of the following are you not required to signal beforehand? a. changing lanes b. speeding up c. stopping