Write a function called count_vowels that accepts a string argument that represents a word and returns the number of vowels that are in the word. The vowels are A, E, I, O, and U (ignore the 'sometimes Y' rule). Count both uppercase and lowercase vowels.

public static int count_vowels(String str){

       String word = str.replaceAll("[^a-zA-Z0-9]", "");

       String text = word.toUpperCase();

       int lenOfString = text.length();

       int count =0;

       for(int i =0; i<lenOfString; i++){

           if(text.charAt(i)=='A'||text.charAt(i)=='E'||text.charAt(i)=='I'

                   ||text.charAt(i)=='O'||text.charAt(i)=='U'){

               count++;

           }

       }

       return count;

   }

Explanation:

This has been implemented using Java programming language.

Firstly, white spaces, special characters and punctions are removed from the string uisng the replaceAll() method

The string is converted to all upper cases

a for loop is used to count the number of vowels and store to a variable count

In the main method a call to count_vowels is done

public class num1 {

   public static void main(String[] args) {

       String name = "David %$ !. gjak";

       System.out.println("The number of vowels in "+name+ " are "+count_vowels(name));

   }

   public static int count_vowels(String str){

       String word = str.replaceAll("[^a-zA-Z0-9]", "");

       String text = word.toUpperCase();

       int lenOfString = text.length();

       int count =0;

       for(int i =0; i<lenOfString; i++){

           if(text.charAt(i)=='A'||text.charAt(i)=='E'||text.charAt(i)=='I'

                   ||text.charAt(i)=='O'||text.charAt(i)=='U'){

               count++;

           }

       }

       return count;

   }

}

The complete program with a Main method is given below

leaning back,   no eye contact,   fidgeting in the seat