Environment and Closure Consider the following program in Scheme: (define f (lambda (x) (lambda (y) (- x y) ) ) ) (let ( (g (f 2)) ;; < (*) (x 3)) (g 4) ) (1) What closure does "(f 2)" return in the line pointed to by the (*) sign? (2) Scheme uses lexical scope rules. Should this program output -2 or -1? If it is -2, explain why it is not -1. If it is -1, explain why it is not -2. Hint: you may assume that the closure is created before the function "g" is called, at the point of "(g (f 2))".