We will pass in a value N. Ouput every even value between 0 and N. Tip: you may remember the modulo operator. 10 % 3 returns the remainder of 10 divided by 3. You can use this in a decision to determine whether a number is odd or even. Just think about what makes an even number even and all should become clear!

def odd_even(N):

   for number in range(0, N+1):

       if number % 2 == 0:

           print(str(number) + " is even")

       elif number % 2 == 1:

           print(str(number) +" is odd")

odd_even(5)

Explanation:

- Create a method called odd_even that takes one parameter, N

- Initialize a for loop that iterates through 0 to N

Inside the loop, check if module of the number with respect to 2 is equal to 0. If yes, print it as even number. If module of the number with respect to 2 is equal to 1, print it as odd number

Call the method

answerfc- file compare;