The Beaufort Wind Scale is used to characterize the strength of winds. The scale uses integer values and goes from a force of 0, which is no wind, up to 12, which is a hurricane. Write a script that generates a random force value between 0 and 12, with use of randi command, Then, it prints a message regarding what type of wind that force represents. The answers should follow this pattern:

See explaination

Explanation:

Script by switch statement

random_force = randi(12) switch(random_force) case 0 disp("There is no wind") case {1,2,3,4,5,6} disp("there is a breeze") case {7,8,9} disp("there is a gale") case {10,11} disp("it is a storm") case 12 disp("Hello Hurricane!") end

First it generates a random force between 1 and 12

Then the switch statement is executed according to the force

in case values of corresponding force are written and their string will be printed according to the case which depends upon the value of random_force

Multiple case values are used because we need multiple values to print the same string

So values {1,2,3,4,5,6} , {7,8,9},{10,11} are combined into one case becuse they all have same value

Script by using nested if-else

random_force = randi(12) //It will genrate a random force value between 1 and 12 which can be used further if random_force == 0 disp("There is no wind") elseif (random_force > 0) && (random_force < 7) disp("there is a breeze") elseif (random_force > 6) && (random_force < 10) disp("there is a gale") elseif (random_force > 9) && (random_force < 12) disp("it is a storm") elseif random_force == 12 disp("Hello Hurricane!") end

First if will check if force is zero and will print its corresponding string

Second,elseif will check if force is between 1 and 6 and will print its corresponding string

third elseif will check if force is between 7 and 9 and will print its corresponding string

Fourth elseif will check if force is 10 or 11 and will print its corresponding string

Last else if will compare value to 12 and return the corresponding string

answer; i believe the answer you're looking for is (nanotechnology);