What is the value of the variable result after these lines of code are executed? >>> a=6
>>> b=2
>>> C=3
>>> result = a*b-alc
The value of the variable is

Write a method named addall that could be placed inside the hashintset class. this method accepts another hashintset as a parameter and adds all elements from that set into the current set, if they are not already present. for example, if a set s1 contains [1, 2, 3] and another set s2 contains [1, 7, 3, 9], the call of s1.addall(s2); would change s1 to store [1, 2, 3, 7, 9] in some order. you are allowed to call methods on your set and/or the other set. do not modify the set passed in. this method should run in o(n) time where n is the number of elements in the parameter set passed in.

Consider the following declarations (1, 2, 3, 5, 7)class bagtype{public: void set(string, double, double, double, double); void print() const; string getstyle() const; double getprice() const; void get(double, double, double, double); bagtype(); bagtype(string, double, double, double, double); private: string style: double l; double w; double h; double price; }; a.) write the definition of the number function set so that private members are set according to the parametersb.) write the definition of the member function print that prints the values of the data membersc.) write the definition of the default constructor of the class bagtype so that the private member variables are initialized to "", 0.0, 0.0, 0.0, 0.0, respectively d.) write a c++ statement that prints the value of the object newbag.e.) write a c++ statement that declares the object tempbag of type bagtype, and initialize the member variables of tempbag to "backpack", 15, 8, 20 and 49.99, respectively

What is a scenario where records stored in a computer frequently need to be checked