Given a double variable named areaofsquare, write the necassary code to read in a value, the area of some square, into areaofsquare and print out the length of that side of that square

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i.e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }

Suppose s, t, and w are strings that have already been created inside main. write a statement or statements, to be added to main, that will determine if the lengths of the three strings are in order by length, smallest to largest. that is, your code should determine if s is strictly shorter than t, and if t is strictly shorter than w. if these conditions hold your code should print (the boolean value) true. if not, your code should print false. (strictly means: no ties) example: if s, t, and w are "cat", "hats", and "skies" your code should print true - their lengths are 3-4-5; but if s, t, and w are "cats" "shirt", and "trust", then print false - their lengths are 4-5-5 enter your code in the box below

How many nibbles can be stored in a 16-bit word?