Write a program second. cpp that takes in a sequence of integers, and prints the second largest number and the second smallest number. Note that in the case of repeated numbers, we really mean the second largest and smallest out of the distinct numbers (as seen in the examples below). You may only use the headers: and . Please have the output formatted exactly like the following examples: (the red is user input)

The program in C++ is as follows:

#include <iostream>

#include <vector>

using namespace std;

int main(){

   int n;

   cout<<"Elements: ";

   cin>>n;

   vector <int>num;

   int input;

   for (int i = 1; i <= n; i++){        cin>>input;        num.push_back(input);    }

   int large, seclarge;

   large = num.at(0);      seclarge = num.at(1);

  if(num.at(0)<num.at(1)){     large = num.at(1);  seclarge = num.at(0);   }

  for (int i = 2; i< n ; i ++) {

     if (num.at(i) > large) {

        seclarge = large;;

        large = num.at(i);

     }

     else if (num.at(i) > seclarge && num.at(i) != large) {

        seclarge = num.at(i);

     }

  }

  cout<<"Second Largest: "<<seclarge<<endl;

  int small, secsmall;

  small = num.at(1);       secsmall = num.at(0);

  if(num.at(0)<num.at(1)){ small = num.at(0);  secsmall = num.at(1);   }

  for(int i=0; i<n; i++) {

     if(small>num.at(i)) {  

        secsmall = small;

        small = num.at(i);

     }

     else if(num.at(i) < secsmall){

        secsmall = num.at(i);

     }

  }

  cout<<"Second Smallest: "<<secsmall;

  return 0;

}

Explanation:

See attachment for explanation

i would say 3 because windows is the best but vista doesnt do updates anymore