What kind of performance issue can arise if you use binary search tree to store strings. What data structure is more efficient than binary search tree to store strings

Ayear in the modern gregorian calendar consists of 365 days. in reality, the earth takes longer to rotate around the sun. to account for the difference in time, every 4 years, a leap year takes place. a leap year is when a year has 366 days: an extra day, february 29th. the requirements for a given year to be a leap year are: the year must be divisible by 4if the year is a century year (1700, 1800, the year must be evenly divisible by 400some example leap years are 1600, 1712, and 2016.write a program that takes in a year and determines whether that year is a leap year.ex: if the input is 1712, the output is: 1712 is a leap year.ex: if the input is 1913, the output is: 1913 is not a leap year.

You receive an email from an impressive-sounding stranger, professor alexander rothschild renard iii, president of the american institute for scientific political statesmen. he urges you to vote for his presidential candidate choice. this social media red flag is known as

Create a string list. 2. use console.readline() to collect values of firstname, lastname, street, city, state, zip, save them to list. 3. write a simple linq statement, call method uppercasewords() to change first letter to uppercase. 4. create a foreach statment to display the information. public static string uppercasewords(string value) { char[] array = value.tochararray(); if (array.length > = 1) { if (char.islower(array[0])) { array[0] = char.toupper(array[0]); } } for (int i = 1; i < array.length; i++) { if (array[i - 1] == ' ') { if (char.islower(array[i])) { array[i] = char.toupper(array[i]); } } } return new string(array);