Given the following code, what logic would you need to include to determine how many times the number 2 appears within the array: int[] myArray = {1,2,3,2,5,6,2,8,2,10};

for (int i = 0; i < myArray. length; i++) {
//your code goes here
}
Sample Output: The number 2 appears 4 times in this array.
NOTE: Your response should be just the missing logic--not the entire problem set.

Analyze the following code. int x = 1; while (0 < x) & & (x < 100) system.out.println(x++); a. the loop runs forever. b. the code does not compile because the loop body is not in the braces. c. the code does not compile because (0 < x) & & (x < 100) is not enclosed in a pair of parentheses. d. the numbers 1 to 99 are displayed. e. the numbers 2 to 100 are displayed.

Show that there is a language a ⚆ {0, 1} â— with the following properties: 1. for all x â a, |x| ≤ 5. 2. no dfa with fewer than 9 states recognizes a. hint: you don’t have to define a explicitly; just show that it has to exist. count the number of languages satisfying (1) and the number of dfas satisfying (2), and argue that there aren’t enough dfas to recognize all those languages. to count the number of languages satisfying (1), think about writing down all the strings of length at most 5, and then to define such a language, you have to make a binary decision for each string about whether to include it in the language or not. how many ways are there to make these choices? to count the number of dfas satisfying (2), consider that a dfa behaves identically even if you rename all the states, so you can assume without loss of generality that any dfa with k states has the state set {q1, q2, . . , qk}. now think about how to count how many ways there are to choose the other four parts of the dfa.

Look at the far left lane in the picture. explain what the red car is doing and what it needs to do to travel safely.