Hey can you me posted picture of question

Two events are occurring:

1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3

Probability of getting an odd number = 3/6 

2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2

The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12 

Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario. 

So correct answer is option C

Three of the six numbers on the die are odd, so the probability of rolling an odd number is 3/6.

One of the two sides of the coin is a head, so the probability of tossing a head is 1/2.

These are considered to be independent events, so the joint probability is the product of these probabilities.

The probability of getting an odd number and a head is
  (3/6)*(1/2) = 3/12

The appropriate choice is ...
  C. 3/12

Gocohcpuccphjvpjvvjiv

1.4 x 10^5 have a nice day!