Write the vertex form of the equation of the parabola which has a vertex of (0,0) and contains the point (1,2). a. y=2x^2. b. y=2(x-1)^2. c. y=x^2. d. y=(x+1)^2+1

General equation of parabola:  y-k = a(x-h)^2

Here the vertex is at (0,0), so we have y-0 = a(x-0)^2, or y = ax^2

All we have to do now is to find the value of the coefficient a.

(1,2) is on the curve.  Therefore, 2 = a(1)^2, or 2 = a(1), or a = 2.

The equation of this parabola is y = 2x^2.

You would need a laid out graph for this but could you provide a picture of just a graph? i can give stepssolve for y.subtract 4xdivide by -1 (opposites)graph slope intercept formcheck each point to see if it’s on the graph