Acircle is centered at (11, −9) and has a radius of 12. what is the equation of the circle? enter the equation in the box using lower case variables x and y.

(x-11)² + (y+9)² = 144

Explanation:
The general form of the equation of the circle is:
(x-h)² + (y-k)² = r²
where:
h is the x-coordinate of the center
k is the y-coordinate of the center
r is the radius of the circle

In the given, we have:
x-coordinate of the center = h = 11
y-coordinate of the center = k = -9
radius of circle = r = 12

Substitute with the givens in the above formula to get the equation as follows:
(x - (11))² + (y - (-9))² = (12)²
(x-11)² + (y+9)² = 144

Hope this helps :)

The answer is option c.