The first-, second-, and third-year enrollment values for a technical school are shown in the table below. enrollment at a technical school year (x) first year f(x) second year s(x) third year t(x) 2009 785 756 756 2010 740 785 740 2011 690 710 781 2012 732 732 710 2013 781 755 800 which of the following statements is true based on the data in the table? the solution to f(x) = s(x) is x = 2,009. the solution to f(x) = s(x) is x = 785. the solution to f(x) = t(x) is x = 2,010. the solution to f(x) = t(x) is x = 740.

The solution to f(x) = t(x) is x = 2010

Option 3 is true.

Step-by-step explanation:

The first-year , second-year , and third-year enrollment values for a technical school are shown in the table below.

Year (x)      First Year f(x)      Second Year s(x)       Third Year t(x)

 2009              785                        756                           756

 2010               740                        785                           740

 2011                690                        710                            781

 2012               732                        732                            710

 2013                781                        755                            800

Now we will check each option.

Option 1: The solution to f(x) = s(x) is x = 2,009

In year 2009, f(x)=s(x)

But 785≠756

Thus, False

Option 2: The solution to f(x) = s(x) is x = 785

x represents year, but 785 it no year

Thus, False

Option 3: The solution to f(x) = t(x) is x = 2010

In year 2010, f(x)=t(x)=740

But 740=740

Thus, True

Option 4: The solution to f(x) = t(x) is x =740

x represents year, but 740 it no year

Thus, False

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x