Triangle abc is similar to triangle jkl, which is formed using jk. what is the length of kl? ? units

Step 1
find the distance AB
A(1,1)  B(3,0)
d=√[(y2-y1)²+(x2-x1)²]> d=√[(0-1)²+(3-1)²]> d=√5

step 2
find the distance JK
J (-5,-1)   K(3,-5)
d=√[(-5+1)²+(3+5)²]> d=√80

step 3
find the scale factor
scale factor=distance JK/distance AB> √80/√5> 4

step 4
find the distance BC
B(3,0)   C(3,3)
d=√[(3-0)²+(3-3)²]> d=3

step 5
find the length of KL
KL=scale factor*distance BC> 4*3=12

the answer is
the length of KL is 12 units

Ibelieve the answer your looking for is d.