Determine b , given that a = 63°, c = 49°, and c = 3.

A=63°
C=49°
c=3
b=?

Solution:
A+B+C=180°
63°+B+49°=180°
B+112°=180°

Solving for B:
B+112°-112°=180°-112°
B=68°

Using Law of Sines:
b/sin B = c/sin C
b/sin 68°=3/sin 49°

Solving for b:
sin 68° (b/sin 68°) = sin 68° (3/sin 49°)

b=3 sin 68°/sin 49°

sin 68°=0.927183855
sin 49°=0.754709580

b=3(0.927183855)/0.754709580
b=3.685591966
b=3.6856