Circle 1 is centered at (−4, −2)(−4, −2) and has a radius of 3 centimeters. circle 2 is centered at (5, 3)(5, 3) and has a radius of 6 centimeters. what transformations can be applied to circle 1 to prove that the circles are similar? enter your answers in the boxes. the circles are similar because you can translate circle 1 using the transformation rule (, ) and then delete it using a scale factor of .

Center of circle 1  = (-4,-2)

Center of circle 2 = (5,3)

From -4 to 5 is a 9 unit move to the right.

From -2 to 3 is a 5 unit move up.

You would need to add 9 to the x value and 5 to the y value.

The transformation rule would be (x+9, y+5)

The radius of circle 2 is twice the length of circle 1, so to make the radius of circle 1 the same as circle 2 multiple it by 2, this is the scale factor.

Scale factor = 2

the correct answer is the second option

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!