If r, rd ( line over rd)is a radius and df (line over df) is a tangent segment. which statement must ve true? a) rd=df b)rd=rf c)triangle rdf is a right triangle d) triangle rdf is an obsltuse triangle

c)Triangle RDF is a right triangle.

Step-by-step explanation:

Let us assume that we have a circle with center R, which has a radius(a line joining the center of a circle to a point on its circumference) RD. Drawing a tangent (a straight line that touches a circle at a point) externally to RD forms an angle of with RD. Also, the tangent is perpendicular to RD if extended.

Therefore if we join R to F, we have a triangle RDF. The suitable option is that triangle RDF is a right triangle.

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?