Complete the square to rewrite y = x^2 + 6x + 3 in vertex form. then state whether the vertex is a maximum or a minimum and give its coordinates. a. maximum at (–3, –6) b. minimum at (3, –6) c. minimum at (–3, –6) d. maximum at (3, –6)

First of all, we convert the equation to a vertex form. 



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The equation in vertex form is . By looking at the equation we can understand that the y value of the vertex point is -6. By further calculation we can verify that the x value of the vertex point is -3. 
Now, there are two ways of finding if the vertex point is a maximum or a minimum. The first way is picking random x coordinates after and before the y vertex value. If the values of y decrease before the y vertex point and increase afterwards, the vertex is a minimum. If the values of y increase before the y vertex point and then decrease afterwards, the vertex is a maximum point. The second way is applying teh second derivative. Here, I will show you the way of doing it:



The result proves two facts about the function:
1. The function has only one vertex/turning point.
2. The vertex/turning point is a minimum (due to the result of the second derivative being positive).

The answer is C.

Ibelieve the answer would be 7, 13, 23